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Created 4 years ago
a = [10,2,3]len(a)3a.reverse()a[3, 2, 10]for i in range(0,20,2):
print(i)
0
2
4
6
8
10
12
14
16
18
a = [10,2,3]len(a)3a.reverse()a[3, 2, 10]for i in range(0,20,2):
print(i)
0
2
4
6
8
10
12
14
16
18