I am not able ti understand the `hash`

function…

I mean how can we check the las condtion where

`list(table) == [('a',99),('b',34)]`

,

because `hash('a') > 'hash('b')`

. So, ‘a’ always comes after ‘b’…

Please tell me where i am wrong and also tell me if i am asking the right question or am i going in the wron direction.

99 isn’t a hash of ‘a’, and 34 isn’t a hash of ‘b’.

The answer depends on how you acquire an index (which hashing function you use - custom built or pythons built-in).

**I have implemented get_valid_index like this…**

**and…**

**The last case is giving False**

When i Digged deeper i found that

`hash('a')`

returns greater value than `hash('b')`

…So, the key-value pair of ‘a’ is inserted after the key-value pair of ‘b’.

What Can I do to TACKLE this ???

Sorry I didn’t understand the first Line.

And i am using the in-built `hash`

function to get hash values…

Actually, tested this a bit, and learned that `hash()`

results differ between runs:

```
hash of 'a': 4481939788840664557, hash('a') % max_size: 3565
hash of 'b': 5206211075269882626, hash('b') % max_size: 770
hash of 'a': 1931782193602269043, hash('a') % max_size: 3955
hash of 'b': -4190295978397739658, hash('b') % max_size: 1398
hash of 'a': 5111666997821574153, hash('a') % max_size: 3081
hash of 'b': 3994030463480646839, hash('b') % max_size: 3255
```

So not necessarily `hash('a')`

> `hash('b')`

The problem may arise when you get actual index. As you can see sometimes the index for key ‘a’ is bigger, sometimes smaller.

To solve it, just sort the table and then compare:

```
sorted(list(table), key=lambda k: k[0]) == [('a', 99), ('b', 34)]
```

OKKK

Now i get it thanks for helping…

Now it’s just fine

also i found an article on stackOverflow…